A perfect Emmy ballot requires every pick to be correct. We do not have a measured probability of that happening; we can show how the arithmetic works under an explicit assumption.
Suppose, hypothetically, that each of your twenty-two picks has a sixty-percent chance of winning and the results are independent. Multiplying 0.6 by itself twenty-two times gives roughly one chance in seventy-six thousand of getting them all right.
That is an illustration, not an estimate of your actual ballot. The assumptions do most of the work.
Why a real ballot is different
Your confidence varies by category. Results can also be related: support for one show might carry into several awards. Multiplying the same probability across the entire card ignores both differences.
The drama and directing comparison provides one historical example of categories worth considering together. It still does not supply a joint probability for this year's nominees.
Our previous article treated an overall incumbent repeat rate as a forecast for a complete ballot. It also claimed the calculation guaranteed nobody in a small pool would get every answer right. Neither claim was justified.
You can win with an imperfect card
A pool is decided by its scoring rules and the other ballots. You do not have to predict every award correctly to finish first, and selecting an unlikely nominee just to be different can leave you further behind.
Make each pick on its merits. Check the tiebreaker rules before submitting, then use the ballot generator if you want a copy to follow during the ceremony.